We know the formula D2/162 which is being used for calculate unit weight of reinforcement per meter.
Here I am willing to explain how it has been arrived D2/162 (Note: D unit is in MM)
Weight of bar per meter = Area of steel bar X Density of steel x Length of bar
= (3.14 x D2/4) x 7850 kg/m3 x 1 m
= D2 X 6162.25/(1000x1000)
= D2 X (0.006162)
= D2 X 1/(0.006162)-1
= (D2/162.28)
The actual value is D2/162.28
Kindly note that this function is only applicable for circular shape steel which density is 7850kg/m3
Hello sir,
ReplyDeletewhy the value 0.006212 is converted into 1/.006212-1.
please tell me.
bro it not -1... its to the power -1
DeleteI understand that it is the inverse but why are we taking the inverse of 0.00616225 D2 is to only get 162 for the ease of saying it as a whole number?
DeleteIt is just for simplicity in calculation
Delete0.00612 is equals to 1/(0.00612)^-1
DeleteYou can easily use both formulas like D2/162 or D2x0.00612
I don't understand after D2 X 1/(0.006162)-1.
ReplyDeleteHow it comes D2/162.28????
its not-1... its (1/0.006162) to the power -1
Deleteits not-1... its (1/0.006162) to the power -1
DeleteWhat is 3.14xd/4
ReplyDeleteArea of bar
DeleteD2 X 6162.25/(1000x1000)
ReplyDeleteWhy do we have to divide 1000 twice plz explain
the unit weight of steel is 7850 kg / m^3
Deletebut we are dealing in mm here so this m3 gets converted into 1000mm multiplied 3 times but see we have mass/unit length on the other side of the equation as well, so shifting unit length on other side of equations gets cancelled with 1ooomm , thus we are left with 2 times 1000mm.
7850kg/(1000*1000*1000) * 3.14 D^2/4 * 1000MM (UNIT LENGTH) = MASS OF STEEL BAR
the unit weight of steel is 7850 kg / m^3
Deletebut we are dealing in mm here so this m3 gets converted into 1000mm multiplied 3 times but see we have mass/unit length on the other side of the equation as well, so shifting unit length on other side of equations gets cancelled with 1ooomm , thus we are left with 2 times 1000mm.
7850kg/(1000*1000*1000) * 3.14 D^2/4 * 1000MM (UNIT LENGTH) = MASS OF STEEL BAR
Weight of the bar for 1 m
Delete= volume × density
= πxd^2/4 x 1m×7850kg/m3
Converting M to MM
= D^2 × 3.14/4 × 1000 × 7850/(1000^3)
= D^2/162
Not clear D2/0.006162 convert in D2/162.28
ReplyDeleteD2×0.006162=D2/(0.006162)-1 =D2/162.28. Now clear
DeleteClick here and learn full explanation step by step
ReplyDeletehttp://civilengineering112.blogspot.com/2017/08/derivation-of-d162-unit-weight-of.html
if you like read more in civil engineer ( in your language click here )
http://civilengineering112.blogspot.com
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ReplyDelete